How to Build a Short-circuit Protection Circuit
Today I am going to make a circuit for Short Circuit protection.This circuit we will make using 12V Relay.
How this circuit will work - when short circuit will occur on the load side then the circuit will be automatically cut off.
Components required -
(1.) Relay - 12V x1
(2.) Push button switch x1
(3.) Battery - 9V x1
(4.) Battery clipper x1
(5.) Connecting wires
(6.) LED - 9V (My LED is of 4V but to make 9V LED I connected 220 ohm resistor to +ve leg of the LED)
(7.) Resistor - 330 ohm x1
(8.) LED 5mm - 3V x2 (Red & Green)
Firstly we have to solder Push button to the common pin and coil-1 pin of the Relay as solder in the picture.
Next solder -ve leg of green LED to coil-1 pin and Normally Open (NO) pin of the Relay as you can see in the picture.
Next connect -ve pin of Red LED to Normally close (NC) pin of the Relay and
Solder +ve leg of Red LED to +ve leg of green LED as solder in the picture.
Next we have to solder 330 ohm resistor between +ve legs of LEDs and coil-2 pin of the Relay as you can see in the picture.
Solder +ve wire of battery clipper to coil-2 pin of Relay and
-ve wire of battery clipper to common pin of the relay as solder in the picture.
Next connect +ve output wire to +ve of battery clipper/coil-2 of relay and
Solder -ve output wire to coil-1 pin of the Relay as picture.
Now our circuit is ready so connect battery to battery clipper.
How it's working - When we will connect battery then Red LED will glow. Now we have to press push button then Green LED will glow.
Now we have to connect 9V LED as load to the output wires.As you can see in the picture 9V LED is glowing.
Unfortunately short circuit occurs on the output wires then circuit will be automatically cut-off.
For again using this circuit press button switch then again 9V LED will glow.
Red LED - shows short circuit occur.
Green LED - Short circuit does not occur.
This type we can make short circuit protection circuit.
How to Build a Short-circuit Protection Circuit
Today I am going to make a circuit for Short Circuit protection.This circuit we will make using 12V Relay.
How this circuit will work - when short circuit will occur on the load side then the circuit will be automatically cut off.
Components required -
(1.) Relay - 12V x1
(2.) Push button switch x1
(3.) Battery - 9V x1
(4.) Battery clipper x1
(5.) Connecting wires
(6.) LED - 9V (My LED is of 4V but to make 9V LED I connected 220 ohm resistor to +ve leg of the LED)
(7.) Resistor - 330 ohm x1
(8.) LED 5mm - 3V x2 (Red & Green)
Firstly we have to solder Push button to the common pin and coil-1 pin of the Relay as solder in the picture.
Next solder -ve leg of green LED to coil-1 pin and Normally Open (NO) pin of the Relay as you can see in the picture.
Next connect -ve pin of Red LED to Normally close (NC) pin of the Relay and
Solder +ve leg of Red LED to +ve leg of green LED as solder in the picture.
Next we have to solder 330 ohm resistor between +ve legs of LEDs and coil-2 pin of the Relay as you can see in the picture.
Solder +ve wire of battery clipper to coil-2 pin of Relay and
-ve wire of battery clipper to common pin of the relay as solder in the picture.
Next connect +ve output wire to +ve of battery clipper/coil-2 of relay and
Solder -ve output wire to coil-1 pin of the Relay as picture.
Now our circuit is ready so connect battery to battery clipper.
How it's working - When we will connect battery then Red LED will glow. Now we have to press push button then Green LED will glow.
Now we have to connect 9V LED as load to the output wires.As you can see in the picture 9V LED is glowing.
Unfortunately short circuit occurs on the output wires then circuit will be automatically cut-off.
For again using this circuit press button switch then again 9V LED will glow.
Red LED - shows short circuit occur.
Green LED - Short circuit does not occur.
This type we can make short circuit protection circuit.
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